Integrand size = 8, antiderivative size = 54 \[ \int x^2 \arcsin (a x) \, dx=\frac {\sqrt {1-a^2 x^2}}{3 a^3}-\frac {\left (1-a^2 x^2\right )^{3/2}}{9 a^3}+\frac {1}{3} x^3 \arcsin (a x) \]
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Time = 0.02 (sec) , antiderivative size = 54, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.375, Rules used = {4723, 272, 45} \[ \int x^2 \arcsin (a x) \, dx=-\frac {\left (1-a^2 x^2\right )^{3/2}}{9 a^3}+\frac {\sqrt {1-a^2 x^2}}{3 a^3}+\frac {1}{3} x^3 \arcsin (a x) \]
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Rule 45
Rule 272
Rule 4723
Rubi steps \begin{align*} \text {integral}& = \frac {1}{3} x^3 \arcsin (a x)-\frac {1}{3} a \int \frac {x^3}{\sqrt {1-a^2 x^2}} \, dx \\ & = \frac {1}{3} x^3 \arcsin (a x)-\frac {1}{6} a \text {Subst}\left (\int \frac {x}{\sqrt {1-a^2 x}} \, dx,x,x^2\right ) \\ & = \frac {1}{3} x^3 \arcsin (a x)-\frac {1}{6} a \text {Subst}\left (\int \left (\frac {1}{a^2 \sqrt {1-a^2 x}}-\frac {\sqrt {1-a^2 x}}{a^2}\right ) \, dx,x,x^2\right ) \\ & = \frac {\sqrt {1-a^2 x^2}}{3 a^3}-\frac {\left (1-a^2 x^2\right )^{3/2}}{9 a^3}+\frac {1}{3} x^3 \arcsin (a x) \\ \end{align*}
Time = 0.03 (sec) , antiderivative size = 41, normalized size of antiderivative = 0.76 \[ \int x^2 \arcsin (a x) \, dx=\frac {1}{9} \left (\frac {\sqrt {1-a^2 x^2} \left (2+a^2 x^2\right )}{a^3}+3 x^3 \arcsin (a x)\right ) \]
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Time = 0.01 (sec) , antiderivative size = 52, normalized size of antiderivative = 0.96
method | result | size |
derivativedivides | \(\frac {\frac {a^{3} x^{3} \arcsin \left (a x \right )}{3}+\frac {a^{2} x^{2} \sqrt {-a^{2} x^{2}+1}}{9}+\frac {2 \sqrt {-a^{2} x^{2}+1}}{9}}{a^{3}}\) | \(52\) |
default | \(\frac {\frac {a^{3} x^{3} \arcsin \left (a x \right )}{3}+\frac {a^{2} x^{2} \sqrt {-a^{2} x^{2}+1}}{9}+\frac {2 \sqrt {-a^{2} x^{2}+1}}{9}}{a^{3}}\) | \(52\) |
parts | \(\frac {x^{3} \arcsin \left (a x \right )}{3}-\frac {a \left (-\frac {x^{2} \sqrt {-a^{2} x^{2}+1}}{3 a^{2}}-\frac {2 \sqrt {-a^{2} x^{2}+1}}{3 a^{4}}\right )}{3}\) | \(52\) |
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Time = 0.25 (sec) , antiderivative size = 40, normalized size of antiderivative = 0.74 \[ \int x^2 \arcsin (a x) \, dx=\frac {3 \, a^{3} x^{3} \arcsin \left (a x\right ) + {\left (a^{2} x^{2} + 2\right )} \sqrt {-a^{2} x^{2} + 1}}{9 \, a^{3}} \]
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Time = 0.17 (sec) , antiderivative size = 48, normalized size of antiderivative = 0.89 \[ \int x^2 \arcsin (a x) \, dx=\begin {cases} \frac {x^{3} \operatorname {asin}{\left (a x \right )}}{3} + \frac {x^{2} \sqrt {- a^{2} x^{2} + 1}}{9 a} + \frac {2 \sqrt {- a^{2} x^{2} + 1}}{9 a^{3}} & \text {for}\: a \neq 0 \\0 & \text {otherwise} \end {cases} \]
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Time = 0.30 (sec) , antiderivative size = 50, normalized size of antiderivative = 0.93 \[ \int x^2 \arcsin (a x) \, dx=\frac {1}{3} \, x^{3} \arcsin \left (a x\right ) + \frac {1}{9} \, a {\left (\frac {\sqrt {-a^{2} x^{2} + 1} x^{2}}{a^{2}} + \frac {2 \, \sqrt {-a^{2} x^{2} + 1}}{a^{4}}\right )} \]
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Time = 0.28 (sec) , antiderivative size = 64, normalized size of antiderivative = 1.19 \[ \int x^2 \arcsin (a x) \, dx=\frac {{\left (a^{2} x^{2} - 1\right )} x \arcsin \left (a x\right )}{3 \, a^{2}} + \frac {x \arcsin \left (a x\right )}{3 \, a^{2}} - \frac {{\left (-a^{2} x^{2} + 1\right )}^{\frac {3}{2}}}{9 \, a^{3}} + \frac {\sqrt {-a^{2} x^{2} + 1}}{3 \, a^{3}} \]
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Timed out. \[ \int x^2 \arcsin (a x) \, dx=\left \{\begin {array}{cl} \frac {\sqrt {\frac {1}{a^2}-x^2}\,\left (\frac {2}{a^2}+x^2\right )}{9}+\frac {x^3\,\mathrm {asin}\left (a\,x\right )}{3} & \text {\ if\ \ }0<a\\ \int x^2\,\mathrm {asin}\left (a\,x\right ) \,d x & \text {\ if\ \ }\neg 0<a \end {array}\right . \]
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